SOLUTION: A,B,and C can finish a job in six days. If B and C work together, the job will take 9 days; if A and C work together, the job will take 8 days. In how many days can each man workin

Algebra ->  Test -> SOLUTION: A,B,and C can finish a job in six days. If B and C work together, the job will take 9 days; if A and C work together, the job will take 8 days. In how many days can each man workin      Log On


   



Question 140876: A,B,and C can finish a job in six days. If B and C work together, the job will take 9 days; if A and C work together, the job will take 8 days. In how many days can each man working alone do the job?
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A,B,and C can finish a job in six days. If B and C work together, the job will take 9 days; if A and C work together, the job will take 8 days. In how many days can each man working alone do the job?
:
Let the completed job = 1
write 3 equations
6%2FA + 6%2FB + 6%2FC = 1
:
9%2FB + 9%2FC = 1
:
8%2FA + 8%2FC = 1
:
Use elimination: mult the eq1 by 3, and eq2 by 2:
18%2FA + 18%2FB + 18%2FC = 3
0%2FA + 18%2FB + 18%2FC = 2
----------------------------------------- Subtraction eliminates B & C, Find A
18%2FA = 1
A = 18 days by himself
:
Use elimination: mult the eq1 by 4, and eq3 by 3:
24%2FA + 24%2FB + 24%2FC = 4
24%2FA + 0%2FB + 24%2FC = 3
----------------------------------------- Subtraction eliminates A & C, Find B
24/B = 1
B = 24 days by himself
:
Use eq2, substitute 24 for B, find C
9%2F24 + 9%2FC = 1
Multiply equation by 24C
9C + 24(9) = 24C
216 = 24C - 9C
216 = 15C
C = 216%2F15
C = 14.4 days by himself
;
Check solutions in eq1
6%2F18 + 6%2F24 + 6%2F14.4 =
.333 + .250 + 4.17 = 1

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
b and c working together take 9 days to do 1 job
b and c working together take 3 days to do 1%2F3 job
b and c working together take 6 days to do 2%2F3 job
a, b and c working together take 6 days to do 1 job
So, a must do 1+-+2%2F3+=+1%2F3 of a job in 6 days
a and c working together take 8 days to do 1 job
a and c working together take 2 days to do 1%2F4 job
a and c working together take 6 days to do 3%2F4 job
Since a does 1%2F3 job in 6 days,
c does 3%2F4+-+1%2F3+=+5%2F12 of a job in 6 days
%281%2F3%29%2F6+%2B+%28b%29%2F6+%2B+%285%2F12%29%2F6+=+1%2F6
1%2F3+%2B+b+%2B+5%2F12+=+1
b+=+12%2F12+-+4%2F12+-+5%2F12
b+=+3%2F12
b+=+1%2F4
So, b does 1%2F4 of a job in 6 days
The question I need to answer is how long does it take each man,
working alone, to do 1 job?
If a does 1%2F3 of a job in 6 days,
he will do 1 job in 3%2A6+=+18 days answer
If b does 1%2F4 of a job in 6 days
he will do 1 job in 4%2A6+=+24 days answer
If c does 5%2F12 of a job in 6 days
he will do 1 job in %2812%2F6%29%2A6+=+14.4 days answer
check answer:
1%2F18+%2B+1%2F24+%2B+1%2F14.4+=+1%2F6
.0555+%2B+.041666+%2B+.069444+=+.1666
.1666+=+.1666
OK