SOLUTION: Please help me solve these problems.
Factor. Check by multiplying
4x^5 y^3+16x^3 y^2+32xy and
9x^2=72x and
factor by grouping
21x^3-15x^2+28x-20.
Thank you very much!
Question 140851: Please help me solve these problems.
Factor. Check by multiplying
4x^5 y^3+16x^3 y^2+32xy and
9x^2=72x and
factor by grouping
21x^3-15x^2+28x-20.
Thank you very much! Answer by jim_thompson5910(35256) (Show Source):
Looking at we can see that the first term is and the last term is where the coefficients are 1 and 8 respectively.
Now multiply the first coefficient 1 and the last coefficient 8 to get 8. Now what two numbers multiply to 8 and add to the middle coefficient 4? Let's list all of the factors of 8:
Factors of 8:
1,2,4,8
-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 8
1*8
2*4
(-1)*(-8)
(-2)*(-4)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4
First Number
Second Number
Sum
1
8
1+8=9
2
4
2+4=6
-1
-8
-1+(-8)=-9
-2
-4
-2+(-4)=-6
None of these pairs of factors add to 4. So the expression cannot be factored