SOLUTION: Please help me solve these problems. Factor. Check by multiplying 4x^5 y^3+16x^3 y^2+32xy and 9x^2=72x and factor by grouping 21x^3-15x^2+28x-20. Thank you very much!

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Please help me solve these problems. Factor. Check by multiplying 4x^5 y^3+16x^3 y^2+32xy and 9x^2=72x and factor by grouping 21x^3-15x^2+28x-20. Thank you very much!      Log On


   



Question 140851: Please help me solve these problems.
Factor. Check by multiplying
4x^5 y^3+16x^3 y^2+32xy and
9x^2=72x and
factor by grouping
21x^3-15x^2+28x-20.
Thank you very much!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1


4x%5E5y%5E3%2B16x%5E3y%5E2%2B32xy Start with the given expression


4xy%28x%5E4y%5E2%2B4x%5E2y%2B8%29 Factor out the GCF 4xy


Now let's focus on the inner expression x%5E4y%5E2%2B4x%5E2y%2B8




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Looking at 1x%5E4y%5E2%2B4x%5E2y%2B8 we can see that the first term is 1x%5E4y%5E2 and the last term is 8 where the coefficients are 1 and 8 respectively.

Now multiply the first coefficient 1 and the last coefficient 8 to get 8. Now what two numbers multiply to 8 and add to the middle coefficient 4? Let's list all of the factors of 8:



Factors of 8:
1,2,4,8

-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 8
1*8
2*4
(-1)*(-8)
(-2)*(-4)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4

First NumberSecond NumberSum
181+8=9
242+4=6
-1-8-1+(-8)=-9
-2-4-2+(-4)=-6

None of these pairs of factors add to 4. So the expression 1x%5E4y%5E2%2B4x%5E2y%2B8 cannot be factored

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Answer:
So 4x%5E5y%5E3%2B16x%5E3y%5E2%2B32xy factors to 4xy%28x%5E4y%5E2%2B4x%5E2y%2B8%29







# 2



9x%5E2=72x Start with the given equation


9x%5E2-72x=0 Subtract 72x from both sides.


9x%28x-8%29=0 Factor out the GCF 9x



Now set each factor equal to zero:

9x=0 or x-8=0


x=0 or x=8 Now solve for x in each case


So our answers are

x=0 or x=8








# 3
21x%5E3-15x%5E2%2B28x-20 Start with the given expression

%2821x%5E3-15x%5E2%29%2B%2828x-20%29 Group like terms


3x%5E2%287x-5%29%2B4%287x-5%29 Factor out the GCF 3x%5E2 out of the first group. Factor out the GCF 4 out of the second group


%283x%5E2%2B4%29%287x-5%29 Since we have the common term 7x-5, we can combine like terms

So 21x%5E3-15x%5E2%2B28x-20 factors to %283x%5E2%2B4%29%287x-5%29