SOLUTION: d. (R and 5 are in absolute value form) {{{R-5<-2}}} e. (0.25w and 1.75 are in absolute value form) {{{0.25-1.75>=1}}} f. (x and 3are in absolute value form) {{{x+3<-2}}}

Algebra ->  Absolute-value -> SOLUTION: d. (R and 5 are in absolute value form) {{{R-5<-2}}} e. (0.25w and 1.75 are in absolute value form) {{{0.25-1.75>=1}}} f. (x and 3are in absolute value form) {{{x+3<-2}}}      Log On


   



Question 140795This question is from textbook an intermediate course in algebra
: d. (R and 5 are in absolute value form)
R-5%3C-2
e.
(0.25w and 1.75 are in absolute value form)
0.25-1.75%3E=1
f. (x and 3are in absolute value form)
x%2B3%3C-2
This question is from textbook an intermediate course in algebra

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
These all work the same way.

abs%28r-5%29%3C-2

So:
r-5%3C-2 or -%28r-5%29%3C-2

r%3C3 or

-r%2B5%3C2
-r%3C-7
r%3E7 (Note inequality sense change when multiplying by a negative)

The solution set, in interval notation: (-infinity,3) U (7,infinity) Notice the parentheses to indicate non-inclusion of the interval end points. The big "U" stands for union.

Work the other two the same way.