SOLUTION: SOLVE BY COMPETING THE SQUARE:
x^2-6x+12=0
PLEASE HELP... I KNOW HOW TO USE THE QUADRATIC FORMULA... BUT I DO NOT KNOW HOW TO DO THE COMPLETING THE SQUARE...
Algebra ->
Matrices-and-determiminant
-> SOLUTION: SOLVE BY COMPETING THE SQUARE:
x^2-6x+12=0
PLEASE HELP... I KNOW HOW TO USE THE QUADRATIC FORMULA... BUT I DO NOT KNOW HOW TO DO THE COMPLETING THE SQUARE...
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Question 140728: SOLVE BY COMPETING THE SQUARE:
x^2-6x+12=0
PLEASE HELP... I KNOW HOW TO USE THE QUADRATIC FORMULA... BUT I DO NOT KNOW HOW TO DO THE COMPLETING THE SQUARE... Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! x^2-6x+12=0
FIRST REMIOVE THE 12 OVER TO THE RIGHT SIDE OF THE = SIGN.
X^2-6X=12
NOW CALCULATE THE NUMBER TO COMPLETE THE SQUARE.
(6/2)^2=3^2=9 WHICH IS THE MISSING TERM THAT MUST BE ADDED TO EACH SIDE OF THE EQUATION
X^2-6X+9=12+9
(X-3)^2=21
TAKE THE SQUARE ROOT OF BOTH SIDES
X-3=SQRT21
ADD 3 TO BOTH SIDES
X=SQRT21+3
X=4.58+3
X=7.58 ANSWER.
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