SOLUTION: This is my first time doing logarithm. and would like to solve for x in these problems. log3+log(x+1)=log5+log(x-3) and ln(2x+3)-ln4=2.Need answer by tomorrow.
thank you
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-> SOLUTION: This is my first time doing logarithm. and would like to solve for x in these problems. log3+log(x+1)=log5+log(x-3) and ln(2x+3)-ln4=2.Need answer by tomorrow.
thank you
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Question 140615This question is from textbook
: This is my first time doing logarithm. and would like to solve for x in these problems. log3+log(x+1)=log5+log(x-3) and ln(2x+3)-ln4=2.Need answer by tomorrow.
thank you This question is from textbook
You can put this solution on YOUR website! log3+log(x+1)=log5+log(x-3)
log(3(x+1))=log(5(x-3))
log(3x+3)=log(5x-15)
10^log(3x+3)=10^log(5x-15)
3x+3=5x-15
2x=18
x=9
.
ln(2x+3)-ln4=2
ln((2x+3)/4)=2
e^ln((2x+3)/4)=e^2
(2x+3)/4=7.38906
2x+3=4*7.38906
2x=29.5562-3
x=26.5562/2
x=13.2781
.
Ed
