SOLUTION: How do I find the starndard form of an ellipse with the equation x^2+4y^2-6x-27=0?

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Question 140415: How do I find the starndard form of an ellipse with the equation x^2+4y^2-6x-27=0?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the standard form of an ellipse with the equation x^2+4y^2-6x-27=0?
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x^2+4y^2-6x-27=0
x^2-6x+9 + 4y^2 = 27+9
(x+3)^2 + 4y^2 = 36
(x+3)^2/36 + y^2/16 = 1
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Cheers,
Stan H.