SOLUTION: Find the domain of the function {{{f(x)=(1)/(3x+2)^2}}}

Algebra ->  Graphs -> SOLUTION: Find the domain of the function {{{f(x)=(1)/(3x+2)^2}}}       Log On


   



Question 140316: Find the domain of the function f%28x%29=%281%29%2F%283x%2B2%29%5E2


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%281%29%2F%283x%2B2%29%5E2 Start with the given function


%283x%2B2%29%5E2=0 Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.


3x%2B2=0 Take the square root of both sides


3x=0-2Subtract 2 from both sides


3x=-2 Combine like terms on the right side


x=%28-2%29%2F%283%29 Divide both sides by 3 to isolate x



x=-2%2F3 Reduce





Since x=-2%2F3 makes the denominator equal to zero, this means we must exclude x=-2%2F3 from our domain

So our domain is:

which in plain English reads: x is the set of all real numbers except x%3C%3E-2%2F3

So our domain looks like this in interval notation


note: remember, the parenthesis excludes -2/3 from the domain

If we wanted to graph the domain on a number line, we would get:

Graph of the domain in blue and the excluded value represented by open circle

Notice we have a continuous line until we get to the hole at x=-2%2F3 (which is represented by the open circle).
This graphically represents our domain in which x can be any number except x cannot equal -2/3