SOLUTION: Graph the equation {{{(x-2)^2+(y+1)^2=12}}}

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Question 140313: Graph the equation %28x-2%29%5E2%2B%28y%2B1%29%5E2=12


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-2%29%5E2%2B%28y%2B1%29%5E2=12 Start with the given equation


%28y%2B1%29%5E2=12-%28x-2%29%5E2 Subtract %28x-2%29%5E2 from both sides


y%2B1=0%2B-sqrt%2812-%28x-2%29%5E2%29 Take the square root of both sides


y=0%2B-sqrt%2812-%28x-2%29%5E2%29-1 Subtract 1 from both sides


So we have the two equations

y=sqrt%2812-%28x-2%29%5E2%29-1 and y=-sqrt%2812-%28x-2%29%5E2%29-1



So when we graph the two equations we get

Graph of y=sqrt%2812-%28x-2%29%5E2%29-1 (red) and y=-sqrt%2812-%28x-2%29%5E2%29-1 (green)