SOLUTION: Graph the equation {{{(x+5)^2+(y-1)^2=16}}}

Algebra ->  Graphs -> SOLUTION: Graph the equation {{{(x+5)^2+(y-1)^2=16}}}       Log On


   

Question 140312: Graph the equation %28x%2B5%29%5E2%2B%28y-1%29%5E2=16


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B5%29%5E2%2B%28y-1%29%5E2=16 Start with the given equation


%28y-1%29%5E2=16-%28x%2B5%29%5E2 Subtract %28x%2B5%29%5E2 from both sides


y-1=0%2B-sqrt%2816-%28x%2B5%29%5E2%29 Take the square root of both sides


y=0%2B-sqrt%2816-%28x%2B5%29%5E2%29%2B1 Add 1 to both sides


So we have the two equations

y=sqrt%2816-%28x%2B5%29%5E2%29%2B1 and y=-sqrt%2816-%28x%2B5%29%5E2%29%2B1



So when we graph the two equations we get

Graph of y=sqrt%2816-%28x%2B5%29%5E2%29%2B1 (red) and y=-sqrt%2816-%28x%2B5%29%5E2%29%2B1 (green)