SOLUTION: Choose three consecutive odd integers such that three times the second decreased by 4 is equal to twice the third increased by 15. Answers (choose one): (a) 11, 13, 15 (b) 13, 15,

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Choose three consecutive odd integers such that three times the second decreased by 4 is equal to twice the third increased by 15. Answers (choose one): (a) 11, 13, 15 (b) 13, 15,       Log On

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Question 140068: Choose three consecutive odd integers such that three times the second decreased by 4 is equal to twice the third increased by 15. Answers (choose one): (a) 11, 13, 15 (b) 13, 15, 17 (c) 23, 25, 27 (d) 25, 27, 29. I don't get how to do this at all. What is "consecutive" anyways? Thanks.
Answer by mathslover(157) About Me  (Show Source):
You can put this solution on YOUR website!
What is "consecutive" anyways?
By consecutive we mean appearing one after the other. So for example 1,3,5 are consecutive odd integers.Again 7,9,11 are similarly 3 consecutive odd integers.
Now to the solution of the actual problem.
Let the three integers
be x,x+2,(x+2)+2 Notice in the example above how they differ by 2.
i.e. x,x+2 and x+ 4 are the 3 consecutive odd integers.
Given
3%2A%28x%2B2%29+-4+ = 2+%2A%28x%2B4%29+%2B+15
3x%2B+6+-4=2x+%2B+8+%2B15
3x+%2B+2 =2x+%2B+23
Group the like terms
3x+-+2x+ = 23+-2
x=21
therefore the other 2 numbers are 23 and 25
Numbers are 21,23,25

Verify
3%2A23+-+4+=+25%2A2+%2B15
69+-4+=+50+%2B+15
65+=+65+