SOLUTION: sample final questions:
write as a single logarithm expression: have no clue how to start:
(#1) -2logbase3(1/x)+1/3logbase3(squa rt OF x)
(#2) 2log2-3logx-1/2[log(
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: sample final questions:
write as a single logarithm expression: have no clue how to start:
(#1) -2logbase3(1/x)+1/3logbase3(squa rt OF x)
(#2) 2log2-3logx-1/2[log(
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Question 139884: sample final questions:
write as a single logarithm expression: have no clue how to start:
(#1) -2logbase3(1/x)+1/3logbase3(squa rt OF x)
(#2) 2log2-3logx-1/2[log(x+3)log(x-2)]
express as sum & difference of logarithms, express powers as factors:
(#3) ln(x^3sqrtx^2+1 /x-3)
solve each equation:
(#4) log(7x+8)=2logx
THANK YOU AND GOD BLESS....THIS IS HELPING ME STUDY WITH THE CORRECT METHOD AND ANSWER.....I TRULY APPRECIATE ALL YOUR HELP AS ALWAYS!!!!
You can put this solution on YOUR website! (#1) -2logbase3(1/x)+1/3logbase3(squa rt OF x)
= -2log3 (x^-1) + (1/3)log3 x^(1/2)
= (-1)(-2)log3 x + (1/2)(1/3)log3 x
= 2log3 x + (1/6) log3 x
= (13/6)log3 x
-------------------------------------
(#2) 2log2-3logx-1/2[log(x+3)log(x-2)]
= 2log2 - logx -(1/2)[log(x+3)log(x-2)]
= log(4/x) -(1/2)log(x+3)*log(x-2)
---------------------------------------
express as sum & difference of logarithms, express powers as factors:
(#3) ln(x^3sqrt[(x^2+1)/(x-3)]
= 3lnx + (1/2)ln[(x^2+1)/(x-3)]
-----------------------------------------
solve each equation:
(#4) log(7x+8)=2logx
log(7x+8) = log x^2
7x+8 = x^2
x^2-7x-8 = 0
(x-8)(x+1) = 0
Potitive solution:
x = 8
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Cheers,
Stan H.
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