SOLUTION: Solve the equation in the interval 0<_ x < 293.14). the equation is: (tan^2)X = sin x sec x

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Question 139636This question is from textbook
: Solve the equation in the interval 0<_ x < 293.14). the equation is: (tan^2)X = sin x sec x This question is from textbook

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation in the interval 0<_ x < 293.14). the equation is:
(tan^2)X = sin x sec x
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tan^2 x = sinx(1/cosx)
tan^2 x -tanx = 0
tanx(tanx-1) = 0
tanx = 0 or tanx-1=0
x = 0 or pi or tanx = 1
x = 0 or pi or x = pi/4 or (5/4)pi
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Cheers,
Stan H.