SOLUTION: If the equation of a circle is x^2+y^2+3x-my+10=0 and the point (2,-5) lies on the circle, what is the value of m? I think it is -6???
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-> SOLUTION: If the equation of a circle is x^2+y^2+3x-my+10=0 and the point (2,-5) lies on the circle, what is the value of m? I think it is -6???
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Question 139615: If the equation of a circle is x^2+y^2+3x-my+10=0 and the point (2,-5) lies on the circle, what is the value of m? I think it is -6??? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If the equation of a circle is x^2+y^2+3x-my+10=0 and the point (2,-5) lies on the circle, what is the value of m? I think it is -6???
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2^2+5^2+3*2+5m+10 = 0
4 + 25 + 6 + 5m + 10 = 0
5m = -45
m = -9
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Cheers,
Stan H.
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