SOLUTION: Container A has a total volume of exactly 3/4 quart. Container B can hold exactly 4/7 of a quart less than 6 quarts. What fraction of container B must be filled in order to hold th

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Container A has a total volume of exactly 3/4 quart. Container B can hold exactly 4/7 of a quart less than 6 quarts. What fraction of container B must be filled in order to hold th      Log On

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Question 1396: Container A has a total volume of exactly 3/4 quart. Container B can hold exactly 4/7 of a quart less than 6 quarts. What fraction of container B must be filled in order to hold the same volume as Container A?
Answer by abhinav75(8) About Me  (Show Source):
You can put this solution on YOUR website!
capacity of container A = 3/4 quarts
capacity of container B = 6 - 4/7 = (6*7 - 4)/7 = 38/7 quarts
the required fraction is (3/4)/(38/7)
= (3*7)/(38*4)
= 21/152
the fraction is 21/152