SOLUTION: find the two-digit number whose tens digits is 4 less than its units digits if the original number is 2 more then 3 times the sum of the digits
Question 139571: find the two-digit number whose tens digits is 4 less than its units digits if the original number is 2 more then 3 times the sum of the digits Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! x = 10's digit
y = units
:
"find the two-digit number whose tens digits is 4 less than its units digits"
x = y - 4
:
"if the original number is 2 more then 3 times the sum of the digits"
10x + y = 2 + 3(x+y)
:
10x + y = 2 + 3x + 3y
:
10x - 3x = 3y - y + 2
:
7x = 2y + 2
Substitute (y-4) for x, find y
7(y-4) = 2y + 2
:
7y - 28 - 2y + 2
:
7y - 2y = 2 + 28
:
5y = 30
y =
y = 6
therefore:
x = 6 - 4 = 2
:
Our solutions is 26
;
Check solution using the statement:
""if the original number is 2 more then 3 times the sum of the digits"
26 = 2 + 3(2+6)
26 = 2 + 24
