SOLUTION: 3/x+3/y divided by 3/x-3/y
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Question 139516
:
3/x+3/y divided by 3/x-3/y
Answer by
stanbon(75887)
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3/x+3/y divided by 3/x-3/y
(3x+3y)/xy / (3y-3x)/xy
Concel the xy denominators:
= [3(x+y)]/[3(y-x)]
Cancel the 3 factor in numerator and denominator.
= (x+y)/(y-x)
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Cheers,
Stan H.