SOLUTION: I know I'm solving for x, so I think I set up the equation like (2x+5)+(3x+1)+(13)+(5x-7)=? My problem is that I don't know what I set it to equal to. <a href="http://s155.ph

Algebra ->  Parallelograms -> SOLUTION: I know I'm solving for x, so I think I set up the equation like (2x+5)+(3x+1)+(13)+(5x-7)=? My problem is that I don't know what I set it to equal to. <a href="http://s155.ph      Log On


   

Question 139411: I know I'm solving for x, so I think I set up the equation like
(2x+5)+(3x+1)+(13)+(5x-7)=? My problem is that I don't know what I set it to equal to.
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Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since the diagonals of a rectangle are equal, this means that we have the equation

%282x%2B5%29%2B%285x-7%29=%283x%2B1%29%2B%2813%29


2x%2B5%2B5x-7=3x%2B1%2B13 Remove the parenthesis



7x-2=3x%2B1%2B13 Combine like terms on the left side


7x-2=3x%2B14 Combine like terms on the right side


7x=3x%2B14%2B2Add 2 to both sides


7x-3x=14%2B2 Subtract 3x from both sides


4x=14%2B2 Combine like terms on the left side


4x=16 Combine like terms on the right side


x=%2816%29%2F%284%29 Divide both sides by 4 to isolate x



x=4 Divide

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Answer:
So our answer is x=4