SOLUTION: Please help me solve the following problem: Twice the smallest of three consecutive odd integers is seven more than the largest. Find the integers. Integers: X= first odd in

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Question 13941: Please help me solve the following problem:
Twice the smallest of three consecutive odd integers is seven more than the largest. Find the integers.
Integers: X= first odd integer, X+2= second integer, X+4 = third integer

I'm trying to figure it out but I'm not coming up with the right answer. According to my book, the answer should be 11, 13, 15...HELP Please! Mike
2X+4+7 = X+2 X+4

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
2x+=+%28x%2B4%29%2B7 Simplify and solve for x.
2x+=+x+%2B+11 Subtract x from both sides.
x+=+11