SOLUTION: I am not sure how to go about this, it was listed in a solution and there is alot of assumptions on the readers behalf or atleast mine. nlog(base4)n=log(base2)4*nlog(base2)n=2nl

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am not sure how to go about this, it was listed in a solution and there is alot of assumptions on the readers behalf or atleast mine. nlog(base4)n=log(base2)4*nlog(base2)n=2nl      Log On


   



Question 13926: I am not sure how to go about this, it was listed in a solution and there is alot of assumptions on the readers behalf or atleast mine.
nlog(base4)n=log(base2)4*nlog(base2)n=2nlog(base2)n
There is a base change from 4 to 2 and I am getting hung up on this one.
nlog(base4)=n(log(base 2)n/log(base 2)4)= n(log(base 2)n-log(base 2)4)=
nlog(base 2)n - nlog(base 2)4
is what I have tried and they don't look the same. Could you please help.
Thanks in advance.
Michael

Found 2 solutions by longjonsilver, MelanieBCC:
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
sorry,
you have 3 expressions on your first line, with 2 "=" signs. This is throwing me. Just quote the question, as given to you please.

Jon.

Answer by MelanieBCC(40) About Me  (Show Source):
You can put this solution on YOUR website!
this is not the answer, but may help you find it...
change of base formula (to convert base to common base 10):
(x and a are positive real numbers, neither = 1)
log%28+a%2C+x+%29+=+log+x%2F+log+a
NOTE: do not simplify to log+%28x%2Fa%29
I hope this helps!