Question 139178: Please help me i really need ur help as soon as possible.
Find three consecutive numbers such that 3 times the middle one shall be greater than the sum of the other two by 15.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find three consecutive numbers such that 3 times the middle one shall be greater than the sum of the other two by 15.
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Three consecutive numbers: x, (x+1), (x+2)
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" 3 times the middle one shall be greater than the sum of the other two by 15."
3(s+1) = x + (x+2) + 15
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3x + 3 = 2x + 17
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3x - 2x = 17 - 3
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x = 14, 15, 16 are the three numbers:
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Check in the statement:
3 times the middle one shall be greater than the sum of the other two by 15.
3(15) = 14 + 16 + 15
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