Question 139057: logb(x) + logx(b) = 7
Find ((logb(x))^2 + ((logx(b))^2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If logb(x) + logx(b) = 7, find ((logb(x))^2 + ((logx(b))^2
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If logb(x) + logx(b) = 7
[logx/logb] + [logb/logx] =7
Multiply thru by logb*logx to get:
(logb(x))^2 + (logx(b))^2 = 7*logb*logx
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So the answer is 7logb*logx
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Cheers,
Stan H.
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