Question 138863This question is from textbook
: 12.47 Regression analysis of free throws by 29 NBA teams during the 2002–2003 season revealed the fitted regression Y = 55.2 + .73X (R2 = .874, syx = 53.2) where Y = total free throws made and X = total free throws attempted. The observed range of X was from 1,620 (New York Knicks) to 2,382 (Golden State Warriors). (a) Find the expected number of free throws made for a team that shoots 2,000 free throws. (b) Do you think that the intercept is meaningful? Hint: Make a scatter plot and let Excel fit the line. (c) Use the quick rule to make a 95 percent prediction interval for Y when X = 2,000.
This question is from textbook
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Regression analysis of free throws by 29 NBA teams during the 2002–2003 season revealed
the fitted regression Y(X) = 55.2 + .73X
(R2 = .874, syx = 53.2)
where Y = total free throws made
and X = total free throws attempted.
-----------------------------------------------
The observed range of X was from 1,620 (New York Knicks) to 2,382 (Golden State Warriors).
(a) Find the expected number of free throws made for a team that shoots 2,000 free throws.
Y(X) = 55.2 + .73X
Y(2000) = 55.2 + 0.73*2000 = 1515,2
-----------------------------------------
(b) Do you think that the intercept is meaningful?
The intercept says 55.2 free throws will be made when zero free throws
are attempted. Hardly realistic.
-------------------------------------
Hint: Make a scatter plot and let Excel fit the line.
(c) Use the quick rule to make a 95 percent prediction interval for Y when X = 2,000.
I'm not familiar with the "Quick Rule".
========================================
Cheers,
Stan H.
|
|
|
