SOLUTION: PROBLEM:
GIVEN THE FUNCTION DEFINED BY: f(x)=x^2-6x+12
A) IDENTIFY THE VERTEX OF THE PARABOLA.
B)DOES THIS PARABOLA OPEN UP OR DOWN?
C)DOES THE VERTEX REPRESENT THE MAXIMUM OR
Algebra ->
Matrices-and-determiminant
-> SOLUTION: PROBLEM:
GIVEN THE FUNCTION DEFINED BY: f(x)=x^2-6x+12
A) IDENTIFY THE VERTEX OF THE PARABOLA.
B)DOES THIS PARABOLA OPEN UP OR DOWN?
C)DOES THE VERTEX REPRESENT THE MAXIMUM OR
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Question 138847: PROBLEM:
GIVEN THE FUNCTION DEFINED BY: f(x)=x^2-6x+12
A) IDENTIFY THE VERTEX OF THE PARABOLA.
B)DOES THIS PARABOLA OPEN UP OR DOWN?
C)DOES THE VERTEX REPRESENT THE MAXIMUM OR MINIMUM POINT OF THE FUNCTION?
D)WHAT IS THE MAXIMUM OF MINIMUM VALUE OF THE FUNCTION f?
E) WHAT IS THE AXIS OF SYMMETRY FOR THIS PARABOLA?
*** IN THIS PROBLEM I HAVE NO UNDERSTANDING OF ANY OF THIS.. I TRIED LOOKING IN THE BOOK FOR A SOLUTION,BUT STILL NO LUCK.. PLEASE HELP???!!
THANKS, lj23kfuller@yahoo.com
You can put this solution on YOUR website! GIVEN THE FUNCTION DEFINED BY: f(x)=x^2-6x+12
A) IDENTIFY THE VERTEX OF THE PARABOLA.
You have a quadratic with a=1 , b=-6, and c = 12
The vertex occurs where x = -b/2a = 6/2 = 3
The corresponding y-value is f(3) = 9-18+12 = 3
The vertex is (3,3)
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B)DOES THIS PARABOLA OPEN UP OR DOWN?
Since the coefficient of the x^2 term is positive, the parabola
opens upward.
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C)DOES THE VERTEX REPRESENT THE MAXIMUM OR MINIMUM POINT OF THE FUNCTION?
Because of what is said in part B, the vertex is a minimum point.
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D)WHAT IS THE MAXIMUM OF MINIMUM VALUE OF THE FUNCTION f?
There is no maximum f value; the minimum value is 3 which occurs where x=3.
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E) WHAT IS THE AXIS OF SYMMETRY FOR THIS PARABOLA?
The axis of symmetry is the vertical line thru the vertex, or x = 3.
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Cheers,
Stan H.
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