SOLUTION: Tutor can you help me with this word problem: A parking lot has a perimeter of 600 feet. The width is 30 ft. less than the length. What are the dimensions of the parking lot?
Algebra ->
Linear-equations
-> SOLUTION: Tutor can you help me with this word problem: A parking lot has a perimeter of 600 feet. The width is 30 ft. less than the length. What are the dimensions of the parking lot?
Log On
Question 138771: Tutor can you help me with this word problem: A parking lot has a perimeter of 600 feet. The width is 30 ft. less than the length. What are the dimensions of the parking lot? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! W=L+30
2L+2(L+30)=600
2L+2L+60=600
4L=600-60
4L=540
L=540/4L=135 FEET FOR THE LENGTH.
W=135+30=165 FEET FOR THE WIDTH.
PROOF
2*135+2*165=600
270+330=600
600=600
(