SOLUTION: (3+3i/1-i)^2
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Question 138737
:
(3+3i/1-i)^2
Answer by
stanbon(75887)
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[(3+3i) / (1-i)]^2
Multiply numerator and denominator by 1+i to get:
= [(3(1+i)^2 / (1+1)]^2
= [(3/2)(1+i)^2]^2
= [(9/4)(1+i)^4]
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Cheers,
Stan H.