Question 138681: I have been working on this problem for the pass two days and all I have is a bunch of mumbule jumbule. Can some work the problen in a way that I can understand it please:)
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Marriage penalty eliminated. The value of the expression
3910 + 0.25(x-28,400)
is the 2003 federal income tax for a single taxpayer with
taxable income of x dollars, where x is over $28,400 but
not over $68,800.
a) Simplify the expression.
b) Find the amount of tax for a single taxpayer with
taxable income of $40,000.
c) Who pays more, a married couple with a joint taxable
income of $80,000 or two single taxpayers with
taxable incomes of $40,000 each?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Marriage penalty eliminated. The value of the expression
3910 + 0.25(x-28,400)
is the 2003 federal income tax for a single taxpayer with
taxable income of x dollars, where x is over $28,400 but
not over $68,800.
a) Simplify the expression.
3910 + 0.25(x-28,400)
= 3910 + 0.25x - 7100
= 3190 + 0.25x
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b) Find the amount of tax for a single taxpayer with
taxable income of $40,000.
3190 + 0.25*40000
3190 = 10,000
=13,190
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c) Who pays more, a married couple with a joint taxable
income of $80,000 or two single taxpayers with
taxable incomes of $40,000 each?
Comment: How is joint in taxed?
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Cheers,
Stan H.
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