SOLUTION: How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm????? I have tried trial and error, but it does not seem to be working. Please help me. Thank you.

Algebra ->  Parallelograms -> SOLUTION: How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm????? I have tried trial and error, but it does not seem to be working. Please help me. Thank you.      Log On


   



Question 138214: How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm????? I have tried trial and error, but it does not seem to be working. Please help me. Thank you.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How do you draw a figure with an area of 64 cm squared and a perimeter of 64 cm
Trial and error will be difficult because I don't think the sides will be integers.
:
Let x = length
Let y = width
:
x*y = 64; area equation
and
2x + 2y = 64; perimeter equation
Simplify, divide by 2
x + y = 32
y = (32-x)
:
Substitute (32-x) for y in the area equation
x(32-x) = 64
32x - x^2 - 64 = 0
Multiply equation by -1, arrange as a quadratic equation:
x^2 - 32x + 64 = 0
:
Use the quadratic formula; a=1; b=-32; c=64
:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
:
x+=+%28-%28-32%29+%2B-+sqrt%28-32%5E2+-+4+%2A+1+%2A+64+%29%29%2F%282%2A1%29+
:
x+=+%2832+%2B-+sqrt%281024+-+256+%29%29%2F%282%29+
If you do the math here you will get two solutions
:
x = 29.8564 or x = 2.1436 One value is the length and the other is the width