SOLUTION: An airplane flies 738 mi against the wind and 1062 mi with the wind in a total time of 9 hours. The speed of the airplane in still air is 200 mi/h. What is the speed of the wind?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: An airplane flies 738 mi against the wind and 1062 mi with the wind in a total time of 9 hours. The speed of the airplane in still air is 200 mi/h. What is the speed of the wind?      Log On


   

Question 138082This question is from textbook Prentice Hall Algebra 1
: An airplane flies 738 mi against the wind and 1062 mi with the wind in a total time of 9 hours. The speed of the airplane in still air is 200 mi/h. What is the speed of the wind? This question is from textbook Prentice Hall Algebra 1

Answer by checkley77(12844) About Me  (Show Source):
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738/(200-W)+1062/(200+W)=9
[738(200+W)+1062(200-W)/(200-W)(200+W)=9
(147,600+738W+212,400-1062W)/(40,000-W^2)=9 NOW CROSS MULTIPLY
9(40,000-W^2)=738W-1062W+147,600+212,400
360,000-9W^2=-324W+360,000
-9W^2+324W+360.000-360,000=0
9W^2-324W=0
9W(W-36)=0
W-26=0
W=36 ANSWER FOR THE SPEED OF THE WIND.
PROOF
738/(200-36)+1062/(200+36)=9
738/164+1062/236=9
4.5+4.5=9
9=9