SOLUTION: A hockey team played 81 games in a season. They won 1 fewer game than three times the number of ties and lost 8 fewer games than they won. How many games did they win? Lose? Tie?

Algebra ->  Conversion and Units of Measurement -> SOLUTION: A hockey team played 81 games in a season. They won 1 fewer game than three times the number of ties and lost 8 fewer games than they won. How many games did they win? Lose? Tie?      Log On


   

Question 137940: A hockey team played 81 games in a season. They won 1 fewer game than three times the number of ties and lost 8 fewer games than they won. How many games did they win? Lose? Tie?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let number of wins = w
Let number of losses = l
Let number of ties = t
w+%2B+l+%2B+t+=+81
w+=+3t+-+1
w+=+l+%2B+8
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3t+=+w+%2B+1
t+=+%28w%2B1%29%2F3
I'll get everything in terms of l
l+%2B+8+%2B+l+%2B+%28w%2B1%29%2F3+=+81
l+%2B+8+%2B+l+%2B+%28l%2B9%29%2F3+=+81
6l+%2B+24+%2B+l+%2B+9+=+243
7l+=+243+-+33
7l+=+210
l+=+30
w+=+l+%2B+8
w+=+38
t+=+%28w%2B1%29%2F3
t+=+39%2F3
t+=+13
There were 38 wins, 30 losses, and 13 ties
check:
w+%2B+l+%2B+t+=+81
38+%2B+30+%2B+13+=+81
81+=+81
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w+=+3t+-+1
38+=+3%2A13+-+1
38+=+38
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w+=+l+%2B+8
38+=+30+%2B+8
38+=+38