Question 13779: jo has 37 coins(all nickels, dimes, and quarters) worth $5.50 she has 4 more quarters than nickels how many dimes does jo have Answer by LilSkittleMd(119) (Show Source):
You can put this solution on YOUR website! There are 3 equations
q=n+4 or -n+q=4 (eq.1)
n+d+q=37 (eq.2)
.05n+.1d+.25q=5.50 (eq.3)
Use the elimination method for 2 of the 3 equations
.05n+.1d+.25q=5.50
-.05n-.05d-.05q=-1.85
.05d+.2q=3.65 (eq.4)
Eliminate the same variable from the unused equation and any other equation
n+d+q=37
-n+q=4
d+2q=4 (eq.5)
Now use the elimination method for equations 4 and 5
.05+.2q=3.65
-.05-.1=-2.05
.1q=1.6
q=16
Plug the value for q into equation 4 or 5
d+2(16)=41
d+32=41
d=9
Now plug in the q and d value into one of the three original equations
n+9+16=37
n+25=37
n=12
There are 16 quarters,12 nickels,9 dimes
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