SOLUTION: solve 3x^2-5x+1=0

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Question 137556: solve 3x^2-5x+1=0
Answer by checkley77(12844) About Me  (Show Source):
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3x^2-5x+1=0
USING THE QUADRATIC EQUATION x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ WE GET:
X=(5+-SQRT[-5^2-4*3*1])/2*3
X=(5+-SQRT[25-12})/6
X=(5+-SQRT13)/6
X=(5+-3.6)/6
X=(5+3.6)/6
X=8.6/6
X=1.43 ANSWER.
X=(5-3.6)/6
X=1.4/6
X=.23 ANSWER.