SOLUTION: Tutor could you please assist and solve this by the substitution method?
3y = x + 5
3x - 9y = -10
I do so very much appreciate your help.
Thank you.
Question 137404This question is from textbook
: Tutor could you please assist and solve this by the substitution method?
3y = x + 5
3x - 9y = -10
I do so very much appreciate your help.
Thank you. This question is from textbook
You can put this solution on YOUR website! 3y = x + 5 ---------------------eq1
3x - 9y = -10 -------------------eq2
We'll solve it three ways:
1. From eq1, we see that x=3y-5 (we subtracted 5 from each side)
Now substitute this into eq2 and we get:
3(3y-5)-9y=-10 or
9y-15-9y=10-------------------------NO solution!!!
2. Multiply eq1 by 3 and we get 9y=3x+15, substitute this into eq2
3x-(3x+15)=-10 or
3x-3x-15=-10-------------------------NO solution!!!!!!
3. re-write eq2 as follows:
3x-3*(3y)=-10 now substitute 3y=x+5 into this:
3x-3(x+5)=-10
3x-3x-15=-10--------------------------NO solution!!!!
The equations are inconsistent---they have no solution. Why?????
Write each equation in slope/intercept form(y=mx+b where m is the slope and b is the y-intercept)
eq1 3y=x+5 or (we divided both sides by 3)
y=(1/3)x + 5/3--------------------slope is 1/3
eq2 3x-9y=-10 subtract 3x from each side
-9y=-3x-10 multiply each side by -1
9y=3x+10 divide each term by 9
y=(1/3)x+10/9---------------------------slope is 1/3
Both equations have a slope of 1/3 which means the lines are parallel
