SOLUTION: Please help me solve the following problems and can you also show the check? pleeeeeeeeease...thx. 13-(2c+2)=2(c+2)+3c 0.7(3x+6)=1.1-(x+2)

Algebra ->  Equations -> SOLUTION: Please help me solve the following problems and can you also show the check? pleeeeeeeeease...thx. 13-(2c+2)=2(c+2)+3c 0.7(3x+6)=1.1-(x+2)       Log On


   



Question 13739: Please help me solve the following problems and can you also show the check? pleeeeeeeeease...thx.
13-(2c+2)=2(c+2)+3c
0.7(3x+6)=1.1-(x+2)

Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
13-(2c+2)=2(c+2)+3c
13-2c-2=2%2Ac%2B2%2A2%2B3c
-2c+13-2=2c+4+3c
-2c+11=2c+3c+4
-2c+11=5c+4
-2c-5c=4-11
-7c=-7
%28-7c%29%2F%28-7%29=%28-7%29%2F%28-7%29
c=1
Check: Substitute c = 1 to equation
13-(2(1)+2)=2(1+2)+3(1)
13-(2+2)=2(3)+3
13 - 4 = 6 + 3
9 = 9 (Q.E.D)

0.7(3x+6)=1.1-(x+2)-------->multiply with 10
7(3x+6) = 11 - 10x - 20
7%2A3x%2B7%2A6+=-10x%2B11+-+20
21x%2B42=-10x-9
21x%2B10x=-9-42
31x=-51
31x%2F31=-51%2F31
x=-51%2F31
Check:
0.7(3x+6)=1.1-(x+2)
%287%2F10%29%283x%2B6%29=11%2F10-%28x%2B2%29
%287%2F10%29%283%2A%28-51%2F31%29%2B6%29=11%2F10-%28%28-51%2F31%29%2B2%29
%287%2F10%29%28-153%2F31%29%2B186%2F31%29=11%2F10-%28%28-51%2F31%29%2B62%2F31%29
%287%2F10%29%28%28-153%2B186%29%2F31%29=11%2F10-%28%28-51%2B62%29%2F31%29
%287%2F10%29%2833%2F31%29=11%2F10-%2811%2F31%29
%287%2A33%2F10%2A31%29=%2811%2A31-11%2A10%29%2F%2810%2A31%29
231%2F310=%28341-110%29%2F310%29
231%2F310=231%2F310 (Q.E.D)
OK