SOLUTION: solve the system x^2+y^2=4 4x^2+9y^2=36
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Question 137374
:
solve the system
x^2+y^2=4
4x^2+9y^2=36
Answer by
oscargut(2103)
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x^2+y^2=4
4x^2+9y^2=36
using 1st eq y^2=4-x^2
using the 2nd one
4x^2+9(4-x^2)=36
-5x^2+36=36
-5x^2=0
then x=0
then
y^2=4
and y=2 or y=-2
Answer: solutions are: x=0,y=2 and x=0,y=-2