SOLUTION: How many ounces of pure water must be added to 80 oz of a 9% salt solution to make a 6% salt solution?
A.
120 oz
B.
60 oz
C.
50 oz
D.
40 oz
Algebra ->
Absolute-value
-> SOLUTION: How many ounces of pure water must be added to 80 oz of a 9% salt solution to make a 6% salt solution?
A.
120 oz
B.
60 oz
C.
50 oz
D.
40 oz
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You can put this solution on YOUR website! How many ounces of pure water must be added to 80 oz of a 9% salt solution to make a 6% salt solution?
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9% solution DATA:
Amt. = 80 oz ; salt = 0.09*80 = 7.2 oz
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Water DATA:
Amt. = x oz ; salt = 0
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Mixture DATA:
Amt. = (80+x)oz ; salt = 0.06(80+x) = 4.8 + 0.06x
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EQUATION:
salt + salt = salt
7.2 + 0 = 4.8+0.06x
0.06x = 2.4
x = 40 oz (amt. of pure water that must be added)
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Cheers,
Stan H.