SOLUTION: Why is it true that at the x-intercept, the value of y is 0, and at the y-intercept, the value of x is 0? Please give 1 or 2 examples please? I would like to say thank you for

Algebra ->  Linear-equations -> SOLUTION: Why is it true that at the x-intercept, the value of y is 0, and at the y-intercept, the value of x is 0? Please give 1 or 2 examples please? I would like to say thank you for       Log On


   



Question 137247This question is from textbook
: Why is it true that at the x-intercept, the value of y is 0, and at the y-intercept, the value of x is 0? Please give 1 or 2 examples please?
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This question is from textbook

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The x-intercept is the point at which the line or curve crosses (intercepts) the x-axis, and, everywhere along the x-axis, the y-coordinate is zero (y = 0).
Similarly, the y-intercept is the point at which the line or curve crosses (intercepts) the y-axis, and, everywhere along the y-axis, the x-coordinate is zero (x = 0).
Example:
Graph the linear equation:
y+=+2x%2B4 and identify the x-intercept and the y-intercept:
graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C2x%2B4%29
You can see from the graph that the x-intercept is (-2, 0) and the y-intercept is (0, 4). You'll notice that the y-coordinate and the x-coordinate, respectively, are zero in the two points.
You could have arrived at this conclusion algebraically:
For the y-intercept, set x = 0 and solve for y.
y+=+2x%2B4 Set x = 0.
y+=+2%280%29%2B4
y+=+4The y-intercept is then (0, 4)
For the x-intercept, set y = 0 and solve for x.
y+=+2x%2B4 Set y = 0.
0+=+2x%2B4 Subtract 4 from both sides.
-4+=+2x Divide both sides b 2.
x+=+-2 The x-intercept is then (-2, 0)