SOLUTION: x-4Square root x+3=0 This is how far I got (x-4)=(Square root x+3)
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Question 137138
This question is from textbook
College Algebra
:
x-4Square root x+3=0
This is how far I got (x-4)=(Square root x+3)
This question is from textbook
College Algebra
Answer by
stanbon(75887)
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x-4Square root x+3=0
x-4sqrt(x+3) = 0
x^2 = 16(x+3)
x^2-16x-3 = 0
x=[16 +- sqrt(16^2-4*-3)]/2
x=[16 +- 16.3707...]/2
x= 16.1854 or x = -0.18545,,
===============
Cheers,
Stan H.