SOLUTION: ln (x + 6) - ln 10 = ln(x-1) - ln 2
Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)]
Question 137064: ln (x + 6) - ln 10 = ln(x-1) - ln 2
Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)] Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! ln (x + 6) - ln 10 = ln(x-1) - ln 2
ln[(x+6)/10] = ln[(x-1)/2]
(x+6)/10 = (x-1)/2
Cross multiply to get:
2x+12 = 10x-10
8x = 22
x = 11/4
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Can you please show me the steps on how to solve this problem along with one like...
log 3x - 2[logx - log(2+y)]
Comment: You can't solve this one because it is not an equation:
log3x -2logx + 2log(2+y)
= log[(3x*2+y)/x^2]
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Cheers,
Stan H.
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