SOLUTION: Here is the problem. Time Traveled on a Visit. Steve leaves Nashville to visit his cousin David in Napa, 80 miles away. He travels at an average speed of 50 mph. One half hour
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-> SOLUTION: Here is the problem. Time Traveled on a Visit. Steve leaves Nashville to visit his cousin David in Napa, 80 miles away. He travels at an average speed of 50 mph. One half hour
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Question 136904: Here is the problem. Time Traveled on a Visit. Steve leaves Nashville to visit his cousin David in Napa, 80 miles away. He travels at an average speed of 50 mph. One half hour later David leaves to visit Steve, traveling at an average seed of 60 mph. How long after David leaves will they meet?
I set it up like this:
50t + 60(t - 1/2)= 80 but the answer to that is 1. I know by doing a line graph that the answer should be 1/2 hr, but how do I set it up to give me the right answer? Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! Nope. You had it set up correctly, but you set it up so that t represented STEVE's travel time, which is, in fact 1 hour. Dave's travel time, according to your equation, is t - 1/2, so 1 - 1/2 = 1/2.
If you wanted Dave's travel time directly, you could have set up the equation like this:
