Question 1369: The area of the circle circumscribed about regular heptagon ABCDEFG is 196(pie). The bisectors of angles A and D intersect at P. Find AP.
Answer by khwang(438)   (Show Source):
You can put this solution on YOUR website! Sol: Let the radius of the circumscribed circle be r,
By area of the circle = pi r^2 = 196 pi, so r^2 = 196, r = 14
Since the bisector of any angle of a regular polygon must pass through
the center of the circumscribed circle. Hence,the bisectors of angles
A and D intersect at P which is just the center of the circle.
So,we have AP = r = 14...Answer
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