SOLUTION: This is a Pythagoreans Therom problem. A right triangle has one leg that is 5cm longer than the other leg. The hypotenuse is 25cm long. Find the length of each leg of the tria

Algebra ->  Expressions-with-variables -> SOLUTION: This is a Pythagoreans Therom problem. A right triangle has one leg that is 5cm longer than the other leg. The hypotenuse is 25cm long. Find the length of each leg of the tria      Log On


   

Question 136640This question is from textbook Algebra 1
: This is a Pythagoreans Therom problem.
A right triangle has one leg that is 5cm longer than the other leg. The hypotenuse is 25cm long. Find the length of each leg of the triangle.

This question is from textbook Algebra 1

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X^2+(X+5)^2=25^2
X^2+X^2+10X+25=625
2X^2+10X+25-625=0
2X^2+10X-600=0
2(X^2+5X-300)=0
2(X+20)(X-15)=0
X-15=0
X=15 ANSWER.
PROOF:
15^2+20^2=25^2
225+400=625
625=625