Question 136630This question is from textbook Prentice Hall Algebra 2
: Find a fourth-degree polynomial equation with integer coefficients that has the given numbers as roots.
The given numbers are 3+ i and -2i
This question is from textbook Prentice Hall Algebra 2
Found 2 solutions by Fombitz, solver91311: Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Complex roots always come in conjugate pairs.
If 3+i is a root, so is 3-i.
If -2i is a root, so is 2i.


Work out the final steps to get the solution.
Post another question if you get stuck.
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! If a polynomial equation has a complex root of the form , then the conjugate of the complex number, is also a root. Therefore, your four roots are , , , and
If any number a is a root of a polynomial equation, then is a factor of the polynomial. Therefore, the factors of your polynomial are , , , and . Just multiply the 4 factors together and you will have your required polynomial. The problem asks for a polynomial equation so remember to set the 4th degree polynomial result equal to 0 at the end.
Hint: Be very careful with your signs when multiplying. Remember that , so something like .
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