SOLUTION: find the x-intercept(s) and he coordinates of the vertex for the parabola y=x^2-4x-12.

Algebra ->  Graphs -> SOLUTION: find the x-intercept(s) and he coordinates of the vertex for the parabola y=x^2-4x-12.      Log On


   

Question 136611: find the x-intercept(s) and he coordinates of the vertex for the parabola
y=x^2-4x-12.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
For any parabola y=ax%5E2%2Bbx%2Bc, the x-coordinate of the vertex is at -b%2F2a. Calculate that value, substitute it for x, and then calculate the y-coordinate value.

The x-intercepts are ordered pairs of the form (x,0), So set the trinomial equal to zero and solve, either by factoring and using the zero product rule, completing the square, or using the quadratic formula.