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Question 136464This question is from textbook
: Could someone please help me with my homework, I just dont get it. I have 2 word problems and 2 other problems.
1. find the exact length of the side of a square which has a diagonal of 100 feet.
2. The hypotenuse of a right triangle measures 100 inches, and one leg measures 50 inches. Find the measure of the other leg.
a. give its length in simplified radical form.
b. Round the answer to the nearest thousandth.
3. 10 the square root of 250x - 10 the square root of 160x + 6 the square root of 10x
4.(the square root of x - 9) ( the square root of x + 9)
This question is from textbook
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1. find the exact length of the side of a square which has a diagonal of 100 feet.
Draw the picture of a square and its diagonal of 100 ft.
Label each of the sides as "x".
Use Pythagoras to get:
100^2 = x^2 + x^2
2x^2 = 100^2
x^2 = 2*100^2
x = 100*sqrt(2) ft.
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2. The hypotenuse of a right triangle measures 100 inches, and one leg measures 50 inches. Find the measure of the other leg.
100^2 = 50^2 + x^2
x^2 = 100^2 - 50^2
x^2 = 7500
x^2 = 2500*3
x = 50*sqrt(3) inches
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a. give its length in simplified radical form.: 50*sqrt(3) inches
b. Round the answer to the nearest thousandth.86.6025...
3. 10 the square root of 250x - 10 the square root of 160x + 6 the square root of 10x
10*sqrt(250)x - 10*sqrt(160)x + 6*sqrt(10)x
= 50*sqrt(10)x - 4*sqrt(10)x + 6*sqrt(10)x
= 52*sqrt(10)x
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4.(the square root of x - 9) ( the square root of x + 9)
Use FOIL:
F: sqrt(x)*sqrt(x) = x
O: 9*sqrt(x)
I:-9*sqrt(x)
L: -9*9= -81
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Ans: x-81
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Cheers,
Stan H.
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