SOLUTION: Hello. I appreciate all that you do here. This is my second time. I was very happy with how the answer was so in depth. Thank you very much. This one question has got me in the mud

Algebra ->  Permutations -> SOLUTION: Hello. I appreciate all that you do here. This is my second time. I was very happy with how the answer was so in depth. Thank you very much. This one question has got me in the mud      Log On


   



Question 136324: Hello. I appreciate all that you do here. This is my second time. I was very happy with how the answer was so in depth. Thank you very much. This one question has got me in the muddle at the moment. I have soem ideas. But a little lost. Here it is.
"Prove that if n is an Integer and log2 is Rational, then log2 n is an Integer?"



Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
"Prove that if n is an Integer and log2 is Rational, then log2 n is an Integer?"
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If n is an integer it is rational and has form c/d.
If log2 is rational it has the form a/b where a,b are integers and b is not zero
Therefore log2 n = [logn]/[log2] = [c/d]/[a/b] = cb/ad, which is rational.
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Cheers,
Stan H.