SOLUTION: Need help Suppose that the heights of adult women in the United States are normally distributed with a mean of 63.5 inches and a standard deviation of 2.4 inches. Jennifer is t

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Question 136143: Need help
Suppose that the heights of adult women in the United States are normally distributed with a mean of 63.5 inches and a standard deviation of 2.4 inches. Jennifer is taller than 90% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places.
Round your answer to at least one decimal place.
Inches =

Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website!
We need to find the SD that yields 90% below it. There are tables of SD that give area between +-SD. Let's use that type of table.
In order to find the SD that gives 90% below, we need to allow for the fact that we are going to include the entire lower half of the normal curve. If we want the upper limit to include 90%, then we will have 40% above the mean.
We need to find the SD value from our table that yields 2*40% = 80% between +-SD. In my table, that is a value of 1.2816.
You can get this from your TI-83 like tis -->http://people.hsc.edu/faculty-staff/robbk/Math121/TI-83/InvStdNormal.html
So Jen is