SOLUTION: I'm the 7th grader's tutor, with one more of the five that gave us problems. {{{(2x/3)-((x-5)/5)=2-((5+3x)/15)}}} Here's our work: {{{10x-3x-15=30-5+3x}}} then {{{7x-15=

Algebra ->  Equations -> SOLUTION: I'm the 7th grader's tutor, with one more of the five that gave us problems. {{{(2x/3)-((x-5)/5)=2-((5+3x)/15)}}} Here's our work: {{{10x-3x-15=30-5+3x}}} then {{{7x-15=      Log On


   

Question 13612: I'm the 7th grader's tutor, with one more of the five that gave us problems.
%282x%2F3%29-%28%28x-5%29%2F5%29=2-%28%285%2B3x%29%2F15%29

Here's our work: 10x-3x-15=30-5%2B3x then 7x-15=25%2B3x
We solved for x and got x=10 but it does not fit when you check it by plugging 10 in for x in the equasion.
Can you help us please? Thanks!
Found 2 solutions by longjonsilver, LilSkittleMd:
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
2 errors...

should be +15
should be -3x

Both errors come from not using the minus sign correctly when multiplying out the brackets.

try that

Jon.

Answer by LilSkittleMd(119) About Me  (Show Source):
You can put this solution on YOUR website!
When figuring out the equation, you forgot to carry the negative into the equation. The equation should be:
10x-3x+15=30-5-3x
Then:
7x-15=25-3x
Then:
10x=10
x=1
The value of x is equal to 1