SOLUTION: Tracy leaves for work at 8:a.m traveling at 36 mph. Sarah finds that Tracy has forgotten her briefcase, so she leaves 8:05 chasing after her at 50 mph. At what time will Sarah catc

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Tracy leaves for work at 8:a.m traveling at 36 mph. Sarah finds that Tracy has forgotten her briefcase, so she leaves 8:05 chasing after her at 50 mph. At what time will Sarah catc      Log On


   

Question 136068This question is from textbook algebra structure and method
: Tracy leaves for work at 8:a.m traveling at 36 mph. Sarah finds that Tracy has forgotten her briefcase, so she leaves 8:05 chasing after her at 50 mph. At what time will Sarah catch tracy? This question is from textbook algebra structure and method

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Tracy leaves for work at 8:a.m traveling at 36 mph. Sarah finds that Tracy has forgotten her briefcase, so she leaves 8:05 chasing after her at 50 mph. At what time will Sarah catch tracy?
:
Change 5 min to hrs: 5/60 = 1%2F12 hrs
Let t = travel time (in hrs), for T to catch up with S
:
When T catches up with S, there will have traveled the same distance
Write a distance equation from this fact: Dist = speed * time
:
T's dist = S's distance
50t = 36(t+1%2F12)
50t = 36t + 36%2F12
50t - 36t = 3
14t = 3
t = 3%2F14
change to minutes and fractional minutes to seconds
60 * 3%2F14 = 12.857 min = 12 min 51 sec
:
8:05 + 12 min 51 sec = 08:17:51 AM, when T catches up with S
:
:
Check solution on calc by finding the distances
36(3%2F14+%2B+1%2F12%29) =
36 * .297 = 10.7 mi
:
50 * 3%2F14 = 10.7 mi