SOLUTION: Please help me with these...thank you The function, p(d) = 1 + d/33 gives the pressure, in atmospheres (atm) at a depth d in the sea (d is in feet). Note that p(0) = 1 atm, p(33

Algebra ->  Functions -> SOLUTION: Please help me with these...thank you The function, p(d) = 1 + d/33 gives the pressure, in atmospheres (atm) at a depth d in the sea (d is in feet). Note that p(0) = 1 atm, p(33      Log On


   

Question 135967: Please help me with these...thank you
The function, p(d) = 1 + d/33 gives the pressure, in atmospheres (atm) at a depth d in the sea (d is in feet). Note that p(0) = 1 atm, p(33) = 2, and so on. Find the pressure at 110 feet.
The pressure at 110 feet is ? atm.
(type an integer or a simplified fraction)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The function, p(d) = 1 + d/33 gives the pressure, in atmospheres (atm) at a depth d in the sea (d is in feet). Note that p(0) = 1 atm, p(33) = 2, and so on.
:
Find the pressure at 110 feet.
p(d) = 1+%2B+d%2F33
:
p(110) = 1+%2B+110%2F33
:
Reduce the fraction to a proper fraction: 110/33 = 3 11%2F33 = 3 1%2F3
so we have:
p(110) = 1 + 31%2F3
:
p(110) = 4 1%2F3 atms